A 9 V battery is connected to a 100 Ω light bulb in a simple circuit. An ammeter measures the current through the light bulb to be 0.09 A. What power is dissipated in the light bulb?

A. 0.01 W
Incorrect. You calculated I divided by V. It should be I multiplied by V.

B. 0.81 W
Correct! This is the power dissipated by the bulb.

C. 1 W
Incorrect. You calculated I times R divided by V. It should be I multiplied by V.

D. 9 W
Incorrect. This is the value of the voltage drop across the bulb, not the power.

A 9 V battery is connected to a 270 Ω resistor. What power is dissipated in the resistor?

A. 0.0333 W
Incorrect. You calculated V divided by R. It should be V squared divided by R.

B. 0.3 W
Correct! This is the power dissipated by the bulb.

C. 3.333 W
Incorrect. You calculated R divided by V squared. It should be V squared divided by R .

D. 30 W
Incorrect. You calculated R divided by V. It should be V squared divided by R.

Two resistors, 270 Ω and 330 Ω, are connected in series to a 9 V battery. What is the power dissipated in the 270 Ω resistor?

A. 0.015 W
Incorrect. 0.015 is the value of the current in amperes.

B. 0.061 W
Correct! This is the power dissipated by the 270 Ohm resistor.

C. 0.074 W
Incorrect. This is the power dissipated by the 330 Ohm resistor.

D. 0.135 W
Incorrect. This is the power provided by the battery.

Two resistors, 270 Ω and 330 Ω, are connected in series to a 9 V battery. What is the power supplied by the battery to the circuit?

A. 0.015 W
Incorrect. 0.015 is the value of the current in amperes.

B. 0.061 W
Incorrect. This is the power dissipated by the 270 Ohm resistor.

C. 0.074 W
Incorrect. This is the power dissipated by the 330 Ohm resistor.

D. 0.135 W
Correct! This is the power provided by the battery.

Two resistors, 68 Ω and 82 Ω, are connected in parallel to a 120 V battery. Determine the power dissipated in the 68 Ω resistor.

A. 96 W
Incorrect. This would be the power delivered by the battery if it were a series circuit.

B. 175.6 W
Incorrect. This is the power dissipated by the 82 Ohm resistor.

C. 211.8 W
Correct! This is the power dissipated by the 68 Ohm resistor.

D. 387.4 W
Incorrect. This is the power delivered by the battery.

Two resistors, 68 Ω and 82 Ω, are connected in parallel to a 120 V battery. What is the power delivered by the battery to the circuit?

A. 96 W
Incorrect. This would be the power delivered by the battery if it were a series circuit.

B. 175.6 W
Incorrect. This is the power dissipated by the 82 Ohm resistor.

C. 211.8 W
Incorrect. This is the power dissipated by the 68 Ohm resistor.

D. 387.4 W
Correct! This is the power delivered by the battery.